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55. A 2 kg block slides on a horizontal floorwith a speed of 4m/s. It strikes auncompressed spring, and compresses ittill the block is motionless. The kineticfriction force is 15 N and spring constantis 10,000N/m. The spring is compressedby:(A) 8.5 cm(B) 5.5 cm(C) 2.5 cm(D) 11.0 cnm

Answer»

As the block is moving with some initial velocity it must be having must KE.

Finally it comes to rest so kinetic energy final will be zero.. it ll have some potential energy.

As frictional force is also given it will some work done by friction.. applyling the work energy theorm...

Work done(external force) + work done (non conservative force ) = change in kinkinetic energy+ change in potential energy.

0 + 15x = kf - ki + pf - pi. 0 + 15x = 0 + 1/2mv2 + k/2x² - 0.

On putting the values you get a qquadric equation i.e, 5000x² - 15x -16=0 solving this equation

x = 0.056m or 5.6 cm

hence, option (b) is correct



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