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56. If poisson's ratio equal to 0.4 for the materialcylindrical wire, then find the percentage changeTRXWX(4)3WRR²x(3)TER?3.(2) 14 kg(4) 12 kgto of 0.5. If a uniform roda longitudinal strain ofe in volume of the rod is(2) 20%90%volume of the same wire in which longitudinaleis 2x103 on applying tensile stress,(1) 0.04%(3) 0.02%(2) 0.08%(4) 4%4.acceleration 19.6 mly in horizontal directhe amount of water split out is(1) 250 kg(2) 500 kg(3) 750 kg(4) 900 kg8 identical drops of the same radius 2through air with steady velocity 5 omis,drops coalesco the terminal velocity wou(1) 10 m/s(2) 0.1 m/s(3) 20 cm/s(4) 40 cm/sBernoulli's principle is based on(1) Conservation of mass(2) Conservation of Energy(3) Conservation of momentum(4) Conservation of VolumeAn open U-tube contains mercury. Wof water is poured into one of the armshow high does the mercury rise in thfrom its initial level ? (Density of13.6 g/cm)(1) 0.56 cm(2) 1.35modulus Y, coefficient ofrea of cross-section A isagnitude of temperaturete the thermal stresslength is L and it is freezontal surface,(2) YAOAT57. Two rods A and B of radii in ratio 1:2 and forratio 2 : 5, are placed between rigid supportsno scope for expansion. The material of bothis same. Now if both the rods are heatedproduce the same temperature rise, then ther.of thermal stress developed in A and B is5.(1) 1:1(2) 1:2(4) Zero(3) 1:4(4) 1:858. Calculate the maximum length of a uniformwhich can be hanged from ceiling, padensitymaterial of wire, g-acceleration due to gravityo=breaking stress for the material of wire.6.(3) 0.41 cm(4) 2.32A closed compartment containgingwith some acceleration in horizontStress |
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Answer» Answer: 57----- The LENGTHS and radii of two rods made of same material are in the ratios 1 : 2 and 2 : 3 respectively ; If the TEMPERATURE difference between the ends for the two rods be the same, then in the steady state, the amount of heat flowing per SECOND through them will be in the RATIO: Medium share Share Answer Correct option is C 8 : 9 Q= d kAδ(T) Q 2 Q 1 = kπ3x 2 δ(T)y kπ2x 2 δ(T)2y Q 2 Q 1 = 9 8
58-------------- If ρ is the density of the material of a wire and σ is the breaking stress, the greatest length of the wire that can hang freely without breaking is? Easy share Share Answer Correct option is A σ/ρg Stress = weight/area =Alρg/A=lρg⇒σ=lρg ∴l=σ/ρg |
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