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6. A copper wire has diameter 0.5 mm andresistivity of 1.6 × 10-8 Ω-m. What will bethe length of this wire to make its resistance10 Ω ? How much does the resistance change ifthe diameter is doubled?

Answer»

Solution:

Area of cross-section of the wire,A=π (d/2)2

Diameter= 0.5 mm = 0.0005 m

Resistance,R= 10 Ω

We know that

∴length of the wire = 122.72m

If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m

Let new resistance be Rʹ

It's not a right answer



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