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6. An object 5 cm high is placed at a distancefocal60 cm in front of a concave mirror oflength 10 cm. Find (i) the position and (ii) size,of the image. |
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Answer» Object distance , u= -60cm Focal lenght , f =-10cm Object size = 5 cm v =? Mirror formula, 1/v + 1/u = 1/f 1/v = 1/u - 1/f 1/v= 1/-(60) +1/-(10) 1/v = -1+6/60 1/v = -5/60 1/v = -1/12 v = -12 Image position = -12 Size of the image, Magnification , m= -v/u m = -(-12)/-60 m = 12/-60 m = 1/-5 m= -0.2 Then , m = h'/h -0.2= h'/5 -0.2 × 5 = h' h' = -1 |
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