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6.Find voltage drop across 4Ω and 6Ω resistance. |
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Answer» net resistance = 4 + [(3)(6)/6+3] = 4 + (18/9) = 4 + 2 = 6ohmnow, current in the circuit = V/R = 3/6 = 0.5A now, voltage across 4ohm = Inet*(4) = 0.5(4) = 2V since, 3 and 6 ohm are connected parallelThey will have same voltagethat is, total voltage - voltage across 4ohm = 3-2 = 1V Thus, voltage across 6ohm = 1V |
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