1.

6 N, 6 N and、72 N actcorner of a cube along three sides as shown in the5.Three forces of magnitudesat afigure given below. Resultant of these forces is72 N6 NO-(1) 12 N angle OB 2) 18 N along OA(3) 18 N along OC (4) 12 N along OE

Answer»

The resultant of lower 6N and 6N , will be √6²+6² = 6√2N = √72N , and the direction will be along OB

now the resultant of √72N and 6√2N(=√72N) , will be along OE... as both the vectors are of same magnitude..

so, the resultant will be √(√72)²+(√72)² = √144 = 12N

so option D.



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