1.

6.The displacement 9 (in meter) of a particle moving aong X axis is given by : X-18t +5tcalculate-(a) the instantaneous velocity at t 4sec.(bjaverage velocity between t4sec and 5sec.

Answer»

Using diffrentiation methodx = 18t + 5t^2dx / dt = 18 + 10tv = 18 + 10tt = 2 secv = 18 + 10 * 2= 18 + 20= 38 m / sect = 3 secv = 18 + 10 * 3= 18 + 20= 48 m / sv(av) =( 38 + 48)/ 2= 43 m/swcdv / dt = 10a = 10 m/ s



Discussion

No Comment Found

Related InterviewSolutions