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`60%` of a first order reaction was completed in `60 min`. The time taken for reactants to decompose to half of their original amount will beA. `45` minB. `60` minC. `40` minD. `50` min |
Answer» Correct Answer - A `60 = (2.303)/(K) "log" (100)/(40)` `t = (2.303)/(K)"log"(100)/(50)` `:. (60)/(t) = (0.40)/(0.310)` `:. t = 45` minutes |
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