1.

`60%` of a first order reaction was completed in `60 min`. The time taken for reactants to decompose to half of their original amount will beA. `45` minB. `60` minC. `40` minD. `50` min

Answer» Correct Answer - A
`60 = (2.303)/(K) "log" (100)/(40)`
`t = (2.303)/(K)"log"(100)/(50)`
`:. (60)/(t) = (0.40)/(0.310)`
`:. t = 45` minutes


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