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`600` kg. of water is to be pumped in a tank per minute under the perssure of `10` g. wt//sq. mm. Find the horse power needed. `1 H.P.=746` watts. |
Answer» Mass of water to be pumped, `m=600 kg`. Volume of water to be pumped, `V=(mass)/(density)=(600)/(10^(3))=0.06 m^(3)`, Pressure `=10` gwt//sq mm. `(10)/(1000)xx9.8 N//(10^(3))^(2) sq m` `=10xx9.8xx10^(3) N//m^(2)` `Power=("workdone")/("time")=("pressure"xx"volume")/("time")` `=((10xx9.8xx10^(3))xx0.6)/(60)=980 watt` `(980)/(746)hp=1.31 hp` |
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