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6222 AmpWYIn the adjoining circuit, thepotential difference across302 is:(a) 2VAV(6) BV(d) 16 V492 |
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Answer» 1/r=1/R1+1/R2 1/r=1/6+1/31/r=1/2r=2r=8 in total v=i×rv=2×8=16v16/4=4v |
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