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6Example 8.6 A car accelerates uniformlyfrom 18 km h to 36 km h in 5 s.Calculate (i) the acceleration and (ill thedistance covered by the car in that time(8.12 |
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Answer» Acceleration = Change in Velocity/Time Change in Velocity = 36-18 = 18 km/h=5 m/s Time= 5 Seconds Acceleration = 5/5= 1 m/s^2 Equation of motion,s=ut+(1/2)at^2 u=18 km/h=5 m/s t=5 s a=1 m/s2 s= (5*5)+(1/2*1*5*5) s=25+12.5 i.e., s=37.5 m |
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