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7.A 100 N force acts horizontally on a block of mass 10 kgplaced on a horizontal rough table of coefficient of frictionu 0.5.If g at the place is 10 ms2, the acceleration of theblock ishl 10 ms-2

Answer»

mass of the block= 10 kgacceleration due to gravity= 10 m/s^2force acting on the block, F =100Ncoefficient of friction, µ= 0.5

the normal force, N= mg=10*10=100 NFriction force, f= µN=0.5*100=50N

the frictional force is acts opposite to the direction of applied force.

let the acceleration of the block be "a"

therefore, F-f=ma=>100-50=10*a=>a=5m/s^2 (answer)



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