InterviewSolution
Saved Bookmarks
| 1. |
7.A 100 N force acts horizontally on a block of mass 10 kgplaced on a horizontal rough table of coefficient of frictionu 0.5.If g at the place is 10 ms2, the acceleration of theblock ishl 10 ms-2 |
|
Answer» mass of the block= 10 kgacceleration due to gravity= 10 m/s^2force acting on the block, F =100Ncoefficient of friction, µ= 0.5 the normal force, N= mg=10*10=100 NFriction force, f= µN=0.5*100=50N the frictional force is acts opposite to the direction of applied force. let the acceleration of the block be "a" therefore, F-f=ma=>100-50=10*a=>a=5m/s^2 (answer) |
|