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7.A ball of mass m is thrown verticaliy up Another ball of mass 2m is thrown at an angle 8 with the vertical. Bothof them stay in air for the same periods of time. What is the ratlo of the height attained by the two balls ? |
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Answer» height obtained by an object thrown up with u velocity (h) = u^2/2g Hence, ratio of the heights (h1/h2) = u1^2/u2^2Also, since they remain in the air for same duration. So, using first law of motion v = u + atv = 0, t = -u/a, Now here, since the a is same as equal to g and t is same, so u needs to be same. Hence, ratio of heights = 1:1 another method another method for this que please send me |
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