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    				| 1. | 7. A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate(i) acceleration in m/s(ii) distance covered by the bus in metres during this interval | 
| Answer» (i) Initial velocity, u = 72 km/h = 72×(5/18) m/s = 20 m/s Final velocity, v = 54 km/h = 54×(5/18) m/s = 15 m/s Time in which velocity changes is, t = 10 s Acceleration, a = (v - u)/t => a = (15 - 20)/10 = -0.5 m/s^2 (ii) distance travelled by the bus Its avg speed over the 10 sec is (15 + 20)/2 = 17.5 m/sec 17.5*10 = 175 meters | |