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7. A hammer of mass 500 g, moving at 50 ms1, strikes anail. The nail stops the hammer in a very short time of0.01 s. What is the force of the nail on the hammer?unctio

Answer»

M = 500g = 0.5 kg

v = 0 m/s

u = 50 m/s

t = 0.01 s

F = m(v-u) / tF = 0.5 (50-0) / 0.01F = 0.5 x 50 x 100 / 1F = 2500 N

Force of nail = 2500 N



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