1.

7. An object is thrown upward to a certain height with a velocity of 3 m/s. Ifthe time required to reach the height is 5s. Calculate the height at whichit was thrown [Hint : (g=10m/s2) (use second equation of motion

Answer»

An object is thrown upward then ,final velocity (v)=0 ,initial velocity (u)=3m/s,time (t)=5sec.Height (s)=?To find S, we find acceleration V=u+at0=3+a×5-3=5a-3/5=ausing second equation of motion S=ut+1/2×a×t square S=3×5+1/2×-3/5×5 squareS=15-3/10×25S=15-15/2S=30-15÷2S=15/2S=7.5m/s

Like my answer if you find it useful!



Discussion

No Comment Found

Related InterviewSolutions