1.

7. Two wires of the same length and the same resistivityare connected in parallel. Find the ratio of their areas ofcross section if the ratio of their electrical resistancesis 4:3​

Answer»

1:4

The resistance of a wire of length l and CROSS section AREA A is given by,

R=ρ(l/A).

So

R2R1=l2l1A1A2=14.

Now current through a wire is   i ∝ 1/R.

∴i2i1 = R1R2 = 41

If their ENDS have the same POTENTIAL differences then currents through them

will be in the ratio of 1:4.



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