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7. Two wires of the same length and the same resistivityare connected in parallel. Find the ratio of their areas ofcross section if the ratio of their electrical resistancesis 4:3 |
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Answer» 1:4 The resistance of a wire of length l and CROSS section AREA A is given by, R=ρ(l/A). So R2R1=l2l1A1A2=14. Now current through a wire is i ∝ 1/R. ∴i2i1 = R1R2 = 41 If their ENDS have the same POTENTIAL differences then currents through them will be in the ratio of 1:4. |
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