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7. While lifting a 10 kg block vertically with a constant velocity, itis kept pressed against a wall by a horizontal force of 49 N.Coefficient of friction between the block and the wall is 0.2.Find the upward force.[Ans. 107.8 N]

Answer»

Frictional force = 0.2×49 =9.8, acting in downward direction.

ER. RAVI KUMAR ROY

Also , weight of block i.e 10×9.8= 98N acts downward& block is moving with constant velocity.Therefore, net force is zero.So, required vertical force = 98+9.8 = 107.8



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