74. A particle moves in a circular path of radius Rwith an angular vel

1.	74. A particle moves in a circular path of radius Rwith an angular velocity o=a-bt where a andb are positive constants and t is time. Themagnitude of the acceleration of the particle aftertime 2a/bis
Answer» Explanation: GIVEN Ш = a-BT We KNOW that v =r Ш = R (a-bt ) The MOTION of the particle is circular a = $\sqrt{ac +at}$ ac = v² /R = R (a -bt )² Given t = 2a/b ac = R ( a - 2a )² = -Ra at = R α α = dШ /d t = -b at = -Rb a = R $\sqrt{a2 +b2}$ Hope you understand This is Habel SABU .............Isn't it the Brainliest...............

74. A particle moves in a circular path of radius Rwith an angular velocity o=a-bt where a andb are positive constants and t is time. Themagnitude of the acceleration of the particle aftertime 2a/bis

Answer»

Explanation:

GIVEN Ш = a-BT

We KNOW that

v =r Ш = R (a-bt )

The MOTION of the particle is circular

a = $\sqrt{ac +at}$

ac = v² /R = R (a -bt )²

Given t = 2a/b

ac = R ( a - 2a )² = -Ra

at = R α

α = dШ /d t = -b

at = -Rb

a = R $\sqrt{a2 +b2}$

Hope you understand

This is Habel SABU .............Isn't it the Brainliest...............

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74. A particle moves in a circular path of radius Rwith an angular velocity o=a-bt where a andb are positive constants and t is time. Themagnitude of the acceleration of the particle aftertime 2a/bis​

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74. A particle moves in a circular path of radius Rwith an angular velocity o=a-bt where a andb are positive constants and t is time. Themagnitude of the acceleration of the particle aftertime 2a/bis