InterviewSolution
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InterviewSolution
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75% of a first order reaction was completed in 32 min . When would 50% of the reaction completedA. 24 minB. 16 minC. 8 minD. 64 min |
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Answer» Correct Answer - b The first order rate constant is given as `k = (2.303)/(t) "log" (a_(0))/(a_(0) - x) ` _______(i) also , half life `t_(1//2) =(2.303 "log"2)/(K)` ______(ii) Equating K from equation (i) and (ii) `therefore (2.303"log"2)/(t_(1//2)) = (2.303)/(32) "log" (100)/(100-75)` or , `("log"2)/(t_(1//2)) = (1)/(32)` log 4 . or `("log"2)/(t_(1//2)) = (1)/(32) xx 2` log 2 `therefore t_(1//2) = 16 ` minutes |
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