1.

8. A 10 g bullet moving at 200 m/s stops afterpenetrating 5 cm of wooden plank. The averageforce exerted on the bullet will be

Answer»

mass=10g=10/1000=0.01kgInitial speed=u=200m/sfinal velocity= o m/sS=5cm=5/100=0.05m

From third equation of motion :V²-u²=2as

0²-(200)²=2ax0.05

-40000=ax5x2/100

-40000=a/10

a=-400000m/s²

From Newton's Second law:F=ma=0.01x(-400000)=-4000N

∴ A force of 4000N acts in opposite direction.



Discussion

No Comment Found

Related InterviewSolutions