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8. A 10 g bullet moving at 200 m/s stops afterpenetrating 5 cm of wooden plank. The averageforce exerted on the bullet will be |
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Answer» mass=10g=10/1000=0.01kgInitial speed=u=200m/sfinal velocity= o m/sS=5cm=5/100=0.05m From third equation of motion :V²-u²=2as 0²-(200)²=2ax0.05 -40000=ax5x2/100 -40000=a/10 a=-400000m/s² From Newton's Second law:F=ma=0.01x(-400000)=-4000N ∴ A force of 4000N acts in opposite direction. |
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