8. A boy throws a ball upwards with velocity v, 20 m/s. The wind impar

1.	8. A boy throws a ball upwards with velocity v, 20 m/s. The wind imparts a horizontal acceleratonnthe left. The angle 0 with the vertical at which the ball must be thrown so that the ball returns to the bis: (g 10 m/s2)(A) tan-1 (1.2)(B) tan-1 (0.2)(D tan1 (0.4)(C) tan-1 (2)
Answer» Solve For Time In Y Direction:Vy = Vyo + AyTime(20 m/s)sin(ang) = (-20 m/s)sin(ang) + (-9.81 m/s^2)TimeTime = (40 m/s)sin(ang)/(9.81 m/s^2) = 4.08sin(ang) Solve For Time In X Direction:Vx = Vxo + AxTime(20 m/s)cos(ang) = (-20 m/s)cos(ang) + (-4.0 m/s^2)TimeTime = (40 m/s)cos(ang)/(4.0 m/s^2) = 10cos(ang) Set Times For X And Y Equal To Each Other:4.08sin(ang) = 10cos(ang)tan(ang) = 4.08/10hence angle is tan^-10.4

8. A boy throws a ball upwards with velocity v, 20 m/s. The wind imparts a horizontal acceleratonnthe left. The angle 0 with the vertical at which the ball must be thrown so that the ball returns to the bis: (g 10 m/s2)(A) tan-1 (1.2)(B) tan-1 (0.2)(D tan1 (0.4)(C) tan-1 (2)

Answer»

Solve For Time In Y Direction:Vy = Vyo + Ay*Time(20 m/s)*sin(ang) = (-20 m/s)*sin(ang) + (-9.81 m/s^2)*TimeTime = (40 m/s)*sin(ang)/(9.81 m/s^2) = 4.08*sin(ang)

Solve For Time In X Direction:Vx = Vxo + Ax*Time(20 m/s)*cos(ang) = (-20 m/s)*cos(ang) + (-4.0 m/s^2)*TimeTime = (40 m/s)*cos(ang)/(4.0 m/s^2) = 10*cos(ang)

Set Times For X And Y Equal To Each Other:4.08*sin(ang) = 10*cos(ang)tan(ang) = 4.08/10hence angle is tan^-10.4

Discussion

No Comment Found

Related InterviewSolutions

7. A body has a weight 50 N in air. Afterimmersing completely in liquid its weight is20 N. Then, the buoyant force on the bodywill be
Name the particulate which causes the disease mentioned below:(a)minamata (b)silicosis.
- Where does a body weight more at the surface of the carth or in a mine?
DelyAbody79entire chainthe ch.57. A body of mass 50gm collides elastically with anotherbody of mass 30 gm at rest. Then the percentage lossof the velocity of the colliding body during collision is1) 25% 2) 75% 3) 50% 4) 67%3) 120380.beide
What will be the acceleration of a body of mass5 kg if a force of 200 N is applied on it?
Rig. 5.168.13 Two bodles of masses 10 kg and 20 kg respectively kept on a smooth, hortzontalsurface are tied to the ends of a light string a horizontal force F 600 Nsapplied to lu A (t) B along the direction of string. What is the tension in thestring in each case
culate the gravitational force befween two protons kept at a distance67 x 10-27 kg. (1 femtometre = 10-15 m)
15. A uniform chain of length 2 m is kept on atable such that a length of 60 cm hangs freelyfrom the edge of the table. The total mass ofthe chain is 4 kg. What is the work done inpulling the entire chain onto the table ?(g = 10 m/s)1) 7.2J273.63) 120J4) 1200
Two block of mass 3 kg and 6 kg respectively are placed on a smooth 1.0 m/shorizontal surface. They are connected by a light spring of force 3 kgconstant k 200 N/m. Initially the spring is unstretched. The indicatedzmvelocities are imparted to the blocks. The maximum extension of thespring will be:A30 cm(C) 20 cm2.0 mls(B) 25 cm(D) 15 cm
88. A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the accelerationof the stone be 9.8 m/s directed towards the ground, calculate the initial velocity of the stone with which itis thrown upwards.

8. A boy throws a ball upwards with velocity v, 20 m/s. The wind imparts a horizontal acceleratonnthe left. The angle 0 with the vertical at which the ball must be thrown so that the ball returns to the bis: (g 10 m/s2)(A) tan-1 (1.2)(B) tan-1 (0.2)(D tan1 (0.4)(C) tan-1 (2)

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment