8. A tennis ball is dropped on the floor from a height of 10 m. It rebounds to a height of 5 m. The ball was incontact with the floor for 0.01 s. What was its averageacceleration during the contact ? (g=10m/s2)(1) 800 m/s2(2) 200 m/s2(3) 1600 m/s2(4) 2400 m/s2

8. A tennis ball is dropped on the floor from a height of 10 m. It r

1.	8. A tennis ball is dropped on the floor from a height of 10 m. It rebounds to a height of 5 m. The ball was incontact with the floor for 0.01 s. What was its averageacceleration during the contact ? (g=10m/s2)(1) 800 m/s2(2) 200 m/s2(3) 1600 m/s2(4) 2400 m/s2
Answer» A tennis BALL is dropped on the floor from a height of 10m. It rebounds to a height of 5m.Time of contact = 0.01 STO Find :Average acceleration of ball during the contact.Solution :❒ We know that, average acceleration is measured as the rate of change of velocity.Third equation of kinematics;v² - u² = 2gH» v denotes final velocity» u denotes initial velocity» g denotes acceleration» H denotes HEIGHTA] Velocity of ball just before IMPACT :➠ v₁² - u₁² = 2gH₁Initial velocity = zero➠ v₁² = 2gH₁➠ v₁ = √2gH₁B] Velocity of ball just after impact :➠ v₂² - u₂² = 2gH₂Final velocity = zero➠ v₂² = 2gH₂➠ v₂ = √2gH₂★ Acceleration of ball :Negative sign shows opposite direction.

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8. A tennis ball is dropped on the floor from a height of 10 m. It rebounds to a height of 5 m. The ball was incontact with the floor for 0.01 s. What was its averageacceleration during the contact ? (g=10m/s2)(1) 800 m/s2(2) 200 m/s2(3) 1600 m/s2(4) 2400 m/s2​

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8. A tennis ball is dropped on the floor from a height of 10 m. It rebounds to a height of 5 m. The ball was incontact with the floor for 0.01 s. What was its averageacceleration during the contact ? (g=10m/s2)(1) 800 m/s2(2) 200 m/s2(3) 1600 m/s2(4) 2400 m/s2