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8. Find out the wavelength of the electronorbiting in the ground state of hydrogenatom. |
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Answer» Radius of ground state of hydrogen atom = 0.53 A° = 0.53*10^-10 m According to de Broglie relation 2pi*r = n*λ For ground state n = 1Then,2*3.14*0.53*10^-10 = 1*λ Therefore, λ = 3.32*10^-10 m= 3.35 A° |
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