1.

8. Find out the wavelength of the electronorbiting in the ground state of hydrogenatom.

Answer»

Radius of ground state of hydrogen atom = 0.53 A° = 0.53*10^-10 m

According to de Broglie relation 2pi*r = n*λ

For ground state n = 1Then,2*3.14*0.53*10^-10 = 1*λ

Therefore, λ = 3.32*10^-10 m= 3.35 A°



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