84. A wire of length 0-26 m is bent to form a circular loop. If 2 A of

1.	84. A wire of length 0-26 m is bent to form a circular loop. If 2 A of current isflowing through this loop, calculate the magnetic field due to this loop at apoint P, which is at a distance of 0-15 m from its centre on its axis.
Answer» We are given a circular current carrying conducting loop. Need to find the magnetic field B (flux density) at a distance d from the center of the loop along the axis of the loop. Using Biot-Savart's law for magnetic field we can derive the formula. Current through the loop = i B = 54 * 10⁻⁶ T d = 4 cm = 0.04 m radius = a = 3 cm = 0.03 m B =μ i a² / [2 (d² + a²)³/² ] 54 * 10⁻⁶ = 4π * 10⁻⁷ * i * 0.03² / [2 * 0.05³] T => i = 1.193 Amp Magnetic field at the center of the loop is given by B = μ i / (2 a) = 4 π * 10⁻⁷ * 1.193 /(2 * 0.03) T = 2.50 * 10⁻⁵ T Like my answer if you find it useful!

84. A wire of length 0-26 m is bent to form a circular loop. If 2 A of current isflowing through this loop, calculate the magnetic field due to this loop at apoint P, which is at a distance of 0-15 m from its centre on its axis.

Answer»

We are given a circular current carrying conducting loop. Need to find the magnetic field B (flux density) at a distance d from the center of the loop along the axis of the loop. Using Biot-Savart's law for magnetic field we can derive the formula.

Current through the loop = i

B = 54 * 10⁻⁶ T

d = 4 cm = 0.04 m

radius = a = 3 cm = 0.03 m

B =μ i a² / [2 (d² + a²)³/² ]

54 * 10⁻⁶ = 4π * 10⁻⁷ * i * 0.03² / [2 * 0.05³] T

=> i = 1.193 Amp

Magnetic field at the center of the loop is given by

B = μ i / (2 a)

= 4 π * 10⁻⁷ * 1.193 /(2 * 0.03) T

= 2.50 * 10⁻⁵ T

Like my answer if you find it useful!

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