1.

`_86A^222rarr_84B^210`. In this reaction, how many `alpha` and `beta` particles are emitted?A. `6alpha , 3 beta`B. `3 alpha , 4 beta`C. `4 alpha , 3 beta`D. `3 alpha, 6 beta`

Answer» Correct Answer - B
Ler `alpha` particles are n and `beta` particles are m. Then,
`86-2n + m = 84 ….(i)`
222 - 4n =210 …(ii)
Solving these two equations, we get n= 3 and
`beta =4.`


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