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`_86A^222rarr_84B^210`. In this reaction, how many `alpha` and `beta` particles are emitted?A. `6alpha , 3 beta`B. `3 alpha , 4 beta`C. `4 alpha , 3 beta`D. `3 alpha, 6 beta` |
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Answer» Correct Answer - B Ler `alpha` particles are n and `beta` particles are m. Then, `86-2n + m = 84 ….(i)` 222 - 4n =210 …(ii) Solving these two equations, we get n= 3 and `beta =4.` |
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