89^2= ____(a) (90-1)^2(b) 90^2(c) 1^2(d) 9^2The question was posed to me in an international level competition.My question is based upon Finding the Square of a Number in chapter Squares and Square Roots of Mathematics – Class 8

89^2= ____(a) (90-1)^2(b) 90^2(c) 1^2(d) 9^2The question was posed to

1.	89^2= ____(a) (90-1)^2(b) 90^2(c) 1^2(d) 9^2The question was posed to me in an international level competition.My question is based upon Finding the Square of a Number in chapter Squares and Square Roots of Mathematics – Class 8
Answer» The correct OPTION is (a) (90-1)^2 For explanation I would SAY: If we have to FIND the square of the number which is near 0 we use the SECOND variation i.e. (90-1)^2. This would help us and make the calculations easier. Therefore (90-1)^2= 90^2-2×90×1+1^2 Therefore (90-1)^2= 8100-180+1 Therefore (90-1)^2=7921.

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