InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A boy has two two rupees coins, one five rupees coins and two ten rupees coins. In what combination should the boy select three coins so the amount is maximum?(a) two five rupees and one ten rupees(b) three ten rupees and one five rupees(c) four two rupees and one ten rupees(d) two ten rupees and one five rupeesThe question was posed to me in final exam.I need to ask this question from Age/Money/Denomination of Currency Word Problems in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right OPTION is (d) two ten rupees and one FIVE rupees |
|
| 2. |
Present ages of Anu and Raj are in the ratio 4:5. Eight years from now the ratio of their ages will be 5:6. Find their present ages.(a) Raj’s age is 32 years and Anu’s age is 40 years(b) Raj’s age is 40 years and Anu’s age is 48 years(c) Raj’s age is 32 years and Anu’s age is 32 years(d) Raj’s age is 40 years and Anu’s age is 32 yearsI got this question at a job interview.Enquiry is from Age/Money/Denomination of Currency Word Problems topic in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct option is (d) RAJ’s AGE is 40 YEARS and Anu’s age is 32 years |
|
| 3. |
Two brothers have their age in the ratio of 2:3. After five years what will be the ratio of their ages. The sum of their ages after 5 years is 30.(a) \(\frac{3}{4}\)(b) \(\frac{4}{3}\)(c) \(\frac{2}{3}\)(d) \(\frac{3}{2}\)This question was addressed to me in a national level competition.I'm obligated to ask this question of Age/Money/Denomination of Currency Word Problems topic in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct answer is (a) \(\frac{3}{4}\) |
|
| 4. |
The notebook costs thirty rupees. How many ten rupees notes will be required to pay the whole amount?(a) 3 notes(b) 4 notes(c) 5 notes(d) 6 notesI have been asked this question in an interview.This is a very interesting question from Age/Money/Denomination of Currency Word Problems in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct answer is (a) 3 notes |
|
| 5. |
If a girl buys an ice cream worth twenty seven rupees and pays the shopkeeper with a note worth fifty rupees. What will be the change she received from the shopkeeper?(a) 27 rupees(b) 23 rupees(c) 22 rupees(d) 21 rupeesI have been asked this question by my college director while I was bunking the class.The above asked question is from Age/Money/Denomination of Currency Word Problems topic in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right option is (B) 23 rupees |
|
| 6. |
At present Rahul’s age is 27 years and Rajiv’s age is 19 years. What is the sum of their ages after five years?(a) 56 years(b) 65 years(c) 46 years(d) 64 yearsThe question was asked by my college professor while I was bunking the class.This key question is from Age/Money/Denomination of Currency Word Problems in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct option is (a) 56 years |
|
| 7. |
A boy has all five rupees coins and he need to pay one hundred and thirty five rupees to a shopkeeper for his grocery. How coins does he need to pay the total amount?(a) 27(b) 28(c) 29(d) 30I got this question in an interview.I want to ask this question from Age/Money/Denomination of Currency Word Problems in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» RIGHT answer is (a) 27 The BEST I can EXPLAIN: The TOTAL amount to be paid is 135 rupees. The BOY has only 5 rupee coins. Let the number of coins required be x. ∴ \(\frac{135}{5}\)=x ∴ 27=x ∴ the boy requires 27 coins in order to pay his billed amount. |
|
| 8. |
If Akshat has twelve two rupees coins and two five rupees coins. What is the total amount with him?(a) 43 rupees(b) 34 rupees(c) 23 rupees(d) 32 rupeesI got this question in quiz.My question is based upon Age/Money/Denomination of Currency Word Problems topic in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» RIGHT answer is (b) 34 rupees The best explanation: Akshat has 12 TWO rupees COINS and 2 five rupees = (2×12)+(2×5) ∴ Total Amount = 24+10 ∴ Total Amount = 34 rupees. |
|
| 9. |
Mohan has to pay two hundred rupees for a book but has only a note of two thousands rupees, what amount will he get back?(a) 2000 rupees(b) 200 rupees(c) 1800 rupees(d) 1400 yearsThe question was posed to me in examination.This intriguing question comes from Age/Money/Denomination of Currency Word Problems in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT answer is (c) 1800 rupees |
|
| 10. |
What will be the solution for equation 3j+2=1-3j.(a) \(\frac{-1}{6}\)(b) \(\frac{1}{6}\)(c) \(\frac{1}{12}\)(d) \(\frac{-1}{12}\)This question was addressed to me in my homework.My question is based upon Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT OPTION is (a) \(\frac{-1}{6}\) The best I can EXPLAIN: 3j+2=1-3j ∴ 3j+3j=1-2 ∴ 6j=-1 ∴ j=\(\frac{-1}{6}\). |
|
| 11. |
Solve: 12x+2=13x-1.(a) 1(b) 2(c) 3(d) 4This question was posed to me during an interview for a job.Enquiry is from Reduce the Given Linear Equations to a Simpler Form in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT OPTION is (C) 3 Explanation: 12x+2=13x-1 ∴ 12x-13x=-1-2 ∴ –x=-3 ∴ x=3. |
|
| 12. |
Sara is twice the age of Marry. The sum total of Sara’s age and Marry’s age after five years is 52. What is Marry’s present age?(a) 14 years(b) 19 years(c) 28 years(d) 33 yearsThe question was posed to me during an internship interview.This is a very interesting question from Age/Money/Denomination of Currency Word Problems topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct option is (c) 28 years |
|
| 13. |
Solve: 13x-2=21x+2.(a) 2x+1=0(b) 2x-1= 0(c) 1 + 2x = 0(d) 1 – 2x = 0The question was posed to me by my college director while I was bunking the class.This intriguing question comes from Reduce the Given Linear Equations to a Simpler Form topic in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT answer is (a) 2x+1=0 |
|
| 14. |
Simplify: t – 12 = 12t – 1.(a) 1+t=0(b) 1-t=0(c) t+1=0(d) t=0This question was posed to me in an online quiz.This interesting question is from Reduce the Given Linear Equations to a Simpler Form in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» RIGHT OPTION is (B) 1-t=0 The explanation is: t – 12 = 12t – 1. ∴ -11t=11 ∴ t=1. |
|
| 15. |
Solve: 12x-13=2x*(11-12).(a) x+\(\frac{13}{14}\)=0(b) x-\(\frac{14}{13}\)=0(c) x=\(\frac{13}{14}\)(d) x+\(\frac{14}{13}\)=0I have been asked this question in an internship interview.My query is from Reduce the Given Linear Equations to a Simpler Form topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» RIGHT OPTION is (c) X=\(\frac{13}{14}\) Explanation: 12x-13=2x*(11-12) ∴ 12x-13=22x-24x ∴ 12x-13= -2x ∴ 14x=13 ∴ x=\(\frac{13}{14}\). |
|
| 16. |
Simplify: \(\frac{13x-1}{12}\)=12.(a) x=\(\frac{13}{145}\)(b) 13x+145=0(c) 13x=145(d) 145x+13=0This question was addressed to me at a job interview.My query is from Reduce the Given Linear Equations to a Simpler Form in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT choice is (c) 13x=145 Explanation: \(\FRAC{13x-1}{12}\)=12 ∴ 13x-1=144 ∴ 13x=145 ∴ X=\(\frac{145}{13}\). |
|
| 17. |
When the equation \(\frac{12x}{2} + \frac{6x}{5}\) = 0 is simplified the solution of the equation would be?(a) x=0(b) x=1(c) x-1=0(d) x+1=0This question was addressed to me by my school principal while I was bunking the class.Origin of the question is Reduce the Given Linear Equations to a Simpler Form topic in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right choice is (a) x=0 |
|
| 18. |
Simplify: \(\frac{2x+1}{2} + \frac{2x-1}{3}\) = 1.(a) 10x = 5(b) 5x = 10(c) 10x + 5 = 0(d) 5x + 10 = 0This question was addressed to me during an interview.Question is taken from Reduce the Given Linear Equations to a Simpler Form topic in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT option is (a) 10X = 5 |
|
| 19. |
Solve: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1.(a) \(\frac{9}{91}\)(b) \(\frac{27}{273}\)(c) \(\frac{-27}{273}\)(d) \(\frac{-9}{91}\)I had been asked this question in homework.The doubt is from Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right CHOICE is (b) \(\frac{27}{273}\) |
|
| 20. |
Solve: 11x – 2 = 7x + 12.(a) –\(\frac{7}{2}\)(b) \(\frac{7}{2}\)(c) \(\frac{14}{2}\)(d) \(\frac{14}{6}\)This question was addressed to me in an online interview.I need to ask this question from Reduce the Given Linear Equations to a Simpler Form topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT option is (B) \(\FRAC{7}{2}\) |
|
| 21. |
Solve: \(\frac{14y-12}{12y-14} = \frac{1}{2}\)(a) \(\frac{10}{16}\)(b) \(\frac{8}{5}\)(c) \(\frac{5}{8}\)(d) \(\frac{16}{10}\)This question was addressed to me in class test.The origin of the question is Reduce the Linear Equation and Find the Value of the Variable topic in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right ANSWER is (c) \(\FRAC{5}{8}\) |
|
| 22. |
Solve: 2x – 3 = 0.(a) \(\frac{3}{2}\)(b) \(\frac{2}{3}\)(c) \(\frac{3}{5}\)(d) \(\frac{5}{3}\)I have been asked this question in unit test.This is a very interesting question from Reduce the Linear Equation and Find the Value of the Variable in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT choice is (a) \(\frac{3}{2}\) |
|
| 23. |
Solve: 2y – 2 = 7y + 1.(a) \(\frac{-3}{5}\)(b) \(\frac{-5}{3}\)(c) \(\frac{2}{3}\)(d) \(\frac{3}{2}\)I had been asked this question during an interview.This intriguing question originated from Reduce the Linear Equation and Find the Value of the Variable in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT ANSWER is (a) \(\FRAC{-3}{5}\) |
|
| 24. |
Solve: 3n – 13 = 13n + 31.(a) \(\frac{22}{5}\)(b) \(\frac{-22}{5}\)(c) \(\frac{-44}{10}\)(d) \(\frac{44}{10}\)I have been asked this question during a job interview.My question is from Reduce the Linear Equation and Find the Value of the Variable topic in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right choice is (b) \(\FRAC{-22}{5}\) |
|
| 25. |
Solve: 0.25(12t – 4) = 1.(a) \(\frac{2}{3}\)(b) \(\frac{3}{2}\)(c) \(\frac{12}{11}\)(d) \(\frac{11}{12}\)This question was posed to me by my school teacher while I was bunking the class.My query is from Reduce the Linear Equation and Find the Value of the Variable topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right ANSWER is (a) \(\frac{2}{3}\) |
|
| 26. |
Solve: \(\frac{2v-3}{2} + \frac{3v}{4}\) = 12.(a) \(\frac{14}{108}\)(b) \(\frac{108}{14}\)(c) \(\frac{59}{7}\)(d) \(\frac{7}{59}\)I got this question in examination.The question is from Reduce the Linear Equation and Find the Value of the Variable topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right choice is (c) \(\frac{59}{7}\) |
|
| 27. |
Solve: 12x – 3 = 9.(a) 1(b) -1(c) 12(d) -12I have been asked this question during an internship interview.Question is from Reduce the Linear Equation and Find the Value of the Variable topic in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» RIGHT answer is (a) 1 The BEST I can EXPLAIN: 12x – 3 = 9 ∴12x = 12 ∴x = 1. |
|
| 28. |
Solve: \(\frac{m-1}{2} + \frac{2m+3}{3}\) = 2.(a) \(\frac{2}{3}\)(b) \(\frac{3}{2}\)(c) 3(d) 2The question was asked in an interview for job.My doubt is from Reduce the Linear Equation and Find the Value of the Variable topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT ANSWER is (a) \(\frac{2}{3}\) |
|
| 29. |
Solve: \(\frac{x}{5} + \frac{x}{7} = \frac{1}{35}\).(a) \(\frac{1}{6}\)(b) \(\frac{1}{8}\)(c) \(\frac{1}{12}\)(d) \(\frac{1}{10}\)I had been asked this question in an internship interview.This interesting question is from Reduce the Linear Equation and Find the Value of the Variable topic in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct OPTION is (c) \(\FRAC{1}{12}\) |
|
| 30. |
Solve: 3(x – 3) = 5(x + 2).(a) \(\frac{-1}{2}\)(b) \(\frac{1}{2}\)(c) 2(d) -2I had been asked this question in unit test.Asked question is from Reduce the Linear Equation and Find the Value of the Variable in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct answer is (a) \(\frac{-1}{2}\) |
|
| 31. |
If the perimeter of a regular hexagon is 192 m then find the Length of each side of the regular hexagon.(a) 32 cm(b) 32 m(c) 23 m(d) 23 cmThis question was addressed to me in final exam.My question is from Applications of Linear Equation (Create and Solve the Equations) in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT answer is (B) 32 m Best explanation: Perimeter of a regular HEXAGON = 6 * (side) ∴ 192 = 6 * (side) ∴ side = 32 m. |
|
| 32. |
Solve: \(\frac{2x-11}{2} + \frac{x}{7}\) = 5.(a) x = \(\frac{147}{16}\)(b) x = \(\frac{16}{147}\)(c) x = \(\frac{14}{167}\)(d) x = \(\frac{167}{14}\)I have been asked this question in an online quiz.My enquiry is from Reduce the Linear Equation and Find the Value of the Variable in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right answer is (a) x = \(\frac{147}{16}\) |
|
| 33. |
If the perimeter of a scalene triangle is 23 cm, with side 1 with Length 12 cm and side 2 with Length 3 cm. Find the Length of third side.(a) 23 cm(b) 12 cm(c) 2 cm(d) 8 cmThis question was addressed to me in homework.I'm obligated to ask this question of Applications of Linear Equation (Create and Solve the Equations) topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right option is (d) 8 cm |
|
| 34. |
If Ram’s present age is 3 years and Shyam is twice Ram’s present age. What will be Shyam’s age after 10 years?(a) 16(b) 17(c) 18(d) 19The question was asked in an internship interview.Asked question is from Applications of Linear Equation (Create and Solve the Equations) in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The CORRECT CHOICE is (a) 16 |
|
| 35. |
Sita wants to buy books of five hundred-rupees and she has 12 fifty-rupees notes. How many notes will she have after the payment?(a) 1(b) 2(c) 3(d) 4The question was asked in a national level competition.This question is from Applications of Linear Equation (Create and Solve the Equations) topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT answer is (b) 2 Best explanation: If Sita wants to pay FIVE hundred-rupees in fifty-rupees notes then she has to give the shopkeeper 10 notes each of fifty-rupees. After giving 10 notes, she will be left with 2 notes. HENCE, the correct answer to this question is 2. |
|
| 36. |
Form an equation for all multiples of 12.(a) 3x(b) 12x(c) 4x(d) 3xThe question was posed to me in an interview for job.This key question is from Applications of Linear Equation (Create and Solve the Equations) topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right answer is (b) 12x |
|
| 37. |
Arya takes a number adds \(\frac{13}{3}\) to it and then divides it by 3. At the end of all operations he gets 12. What would be the original number?(a) \(\frac{23}{3}\)(b) \(\frac{3}{23}\)(c) 23(d) 3I got this question in a job interview.I'd like to ask this question from Applications of Linear Equation (Create and Solve the Equations) in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct choice is (a) \(\frac{23}{3}\) |
|
| 38. |
Raj buys books worth rupees four hundred, he has coins of denomination two-rupees. How many coins does he need to pay the bill?(a) 200(b) 100(c) 400(d) 150The question was asked in a national level competition.Origin of the question is Applications of Linear Equation (Create and Solve the Equations) in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct option is (a) 200 |
|
| 39. |
When a number is subtracted from 484, we get 459. The number subtracted is square of?(a) 5(b) 4(c) 3(d) 2I got this question during an internship interview.I need to ask this question from Applications of Linear Equation (Create and Solve the Equations) topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct choice is (a) 5 |
|
| 40. |
The digits of a two-digit number differ by 4. If the digits are interchanged, and the resulting number is added to the original number, we get 152. What can be the original number?(a) 95(b) 40(c) 73(d) 59This question was posed to me by my school teacher while I was bunking the class.My doubt is from Applications of Linear Equation (Create and Solve the Equations) topic in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT answer is (a) 95 Easy EXPLANATION: Let us take the two DIGIT number such that the digit in the units place is x. The digit in tens place differs by 4 ∴ the digit in tens place is (x + 4). ∴the two digit number obtained = [10 * (x + 4)] + [x] ∴the two digit number obtained = 10x + 40 + x ∴the two digit number obtained = 11x + 40 When the digits are interchanged we obtain the number = [10 * x] + [(x + 4)] The new number obtained = 11x + 4 As we know the original number and the new number add up to 152. ∴ [11x + 40] + [11x + 4] = 152 ∴ 22x + 44 = 152 ∴ 22x = 110 ∴ x = 5 The original number = [10 * ( x + 4 )] + [x] The original number = 11x + 40 The original number = 11 * (5) + 40 The original number = 55 + 40 The original number = 95. |
|
| 41. |
Jon is thrice as old as Kavya. Five years ago his age was two times Kavya’s age. Find their present age.(a) Kavya’s age = 15 years; Jon’s age = 5 years(b) Kavya’s age = 5 years; Jon’s age = 15 years(c) Kavya’s age = 5 years; Jon’s age = 5 years(d) Kavya’s age = 15 years; Jon’s age = 15 yearsThe question was asked during an online interview.Question is from Applications of Linear Equation (Create and Solve the Equations) topic in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct ANSWER is (b) Kavya’s age = 5 YEARS; Jon’s age = 15 years |
|
| 42. |
If Raj scores 27 marks less than the highest scorer and the highest scorer has 2 marks less than the maximum achievable score, then find the score that Raj scored, if the maximum achievable score is 100.(a) 70(b) 71(c) 72(d) 73This question was posed to me in an interview.I would like to ask this question from Solving Linear Equations with Variables on Both the Sides topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct answer is (b) 71 |
|
| 43. |
When two integers are added the sum is -52. If the integers are in the ratio 6:7, then find the integers.(a) -24 and 28(b) 24 and -28(c) -24 and -28(d) 24 and 28This question was addressed to me in exam.This interesting question is from Solving Linear Equations with Variables on Both the Sides in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct choice is (C) -24 and -28 |
|
| 44. |
Sum of consecutive multiples of 23 is 1656. Find the multiples.(a) 529, 552, 575(b) 629, 662, 675(c) 189, 222, 275(d) 389, 332, 375I have been asked this question during a job interview.I want to ask this question from Solving Linear Equations with Variables on Both the Sides in division Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct choice is (a) 529, 552, 575 |
|
| 45. |
If the perimeter of square is 28 m. Find the length of the side.(a) 7 cm(b) 7 m(c) 14 m(d) 11 mThis question was posed to me in an international level competition.Origin of the question is Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct answer is (B) 7 m |
|
| 46. |
The sum of two natural numbers is 5, the numbers are in a ratio 2:3. Find the numbers.(a) 2 and 3(b) 1 and 4(c) 0 and 5(d) 2 and 4The question was posed to me in unit test.Asked question is from Solving Linear Equations with Variables on Both the Sides in chapter Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct choice is (a) 2 and 3 |
|
| 47. |
The sum of three consecutive numbers is 789, what are those consecutive numbers?(a) 262, 263 and 264(b) 263, 264 and 265(c) 264, 265 and 266(d) 265, 266 and 267I got this question in an internship interview.The query is from Solving Linear Equations with Variables on Both the Sides in section Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» The correct answer is (a) 262, 263 and 264 |
|
| 48. |
Bansal has 7 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of rupees 95, how many coins of each denomination does he have?(a) 5 two-rupee and 2 five-rupee(b) 15 two-rupee and 5 five-rupee(c) 5 two-rupee and 15 five-rupee(d) 15 two-rupee and 5 five-rupeeThe question was posed to me in final exam.My doubt is from Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Correct option is (b) 15 two-rupee and 5 five-rupee |
|
| 49. |
Linear equation in one variable has ________ number of solution/s.(a) one(b) one and only one(c) two(d) infiniteThis question was addressed to me in an international level competition.The query is from Applications of Linear Equation (Just Solving the Equations) in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» CORRECT ANSWER is (b) ONE and only one Explanation: The number of solution of any equation depends on the degree of the equation (degree is the highest power of the equation. Example x^2+x-2=0 here the degree of the equation is 2 as the highest power in this equation is 2). Since the linear equation in one variable has it’s degree as 1 ALWAYS, therefore the answer WOULD be ‘one and only one solution’. The option ‘one’ is not accurate and hence one should select ‘one and only one’. |
|
| 50. |
The perimeter of a rectangle is 12 cm and it’s breadth is 2 cm. What will be it’s length?(a) 2 cm(b) 3 cm(c) 4 cm(d) 5 cmI had been asked this question in class test.The query is from Solving Linear Equations with Variables on Both the Sides in portion Linear Equations in One Variable of Mathematics – Class 8 |
|
Answer» Right answer is (b) 3 CM |
|