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Solve: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1.(a) \(\frac{9}{91}\)(b) \(\frac{27}{273}\)(c) \(\frac{-27}{273}\)(d) \(\frac{-9}{91}\)I had been asked this question in homework.The doubt is from Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer»

Right CHOICE is (b) \(\frac{27}{273}\)

The BEST explanation: \(\frac{3x+7}{12} + \frac{22x-1}{3}\) = 1

∴ \(\frac{3*(3x+7)+12*(22x-1)}{12*3}\) = 1

∴ 9x + 21 + 264x – 12 = 36

∴ 273x + 9 = 36

∴ 273x = 27

∴ x = \(\frac{27}{273} = \frac{9}{91}\).



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