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What will be the solution for equation 3j+2=1-3j.(a) \(\frac{-1}{6}\)(b) \(\frac{1}{6}\)(c) \(\frac{1}{12}\)(d) \(\frac{-1}{12}\)This question was addressed to me in my homework.My question is based upon Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8 |
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Answer» CORRECT OPTION is (a) \(\frac{-1}{6}\) The best I can EXPLAIN: 3j+2=1-3j ∴ 3j+3j=1-2 ∴ 6j=-1 ∴ j=\(\frac{-1}{6}\). |
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