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What will be the solution for equation 3j+2=1-3j.(a) \(\frac{-1}{6}\)(b) \(\frac{1}{6}\)(c) \(\frac{1}{12}\)(d) \(\frac{-1}{12}\)This question was addressed to me in my homework.My question is based upon Reduce the Given Linear Equations to a Simpler Form topic in portion Linear Equations in One Variable of Mathematics – Class 8

Answer» CORRECT OPTION is (a) \(\frac{-1}{6}\)

The best I can EXPLAIN: 3j+2=1-3j

∴ 3j+3j=1-2

∴ 6j=-1

∴ j=\(\frac{-1}{6}\).


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