Arya takes a number adds \(\frac{13}{3}\) to it and then divides it by 3. At the end of all operations he gets 12. What would be the original number?(a) \(\frac{23}{3}\)(b) \(\frac{3}{23}\)(c) 23(d) 3I got this question in a job interview.I'd like to ask this question from Applications of Linear Equation (Create and Solve the Equations) in chapter Linear Equations in One Variable of Mathematics – Class 8

Arya takes a number adds \(\frac{13}{3}\) to it and then divides it by

1.	Arya takes a number adds \(\frac{13}{3}\) to it and then divides it by 3. At the end of all operations he gets 12. What would be the original number?(a) \(\frac{23}{3}\)(b) \(\frac{3}{23}\)(c) 23(d) 3I got this question in a job interview.I'd like to ask this question from Applications of Linear Equation (Create and Solve the Equations) in chapter Linear Equations in One Variable of Mathematics – Class 8
Answer» Correct choice is (a) \(\frac{23}{3}\) The explanation: Let the number chosen by Arya be x. The FIRST operation CARRIED out by Arya was adding \(\frac{13}{3}\) to the number. Hence, the equation formed is x + \(\frac{13}{3}\) = 12 The second operation is to DIVIDE throughout by 3. Hence, the equation is modified to \(\frac{x}{3} + \frac{13}{9}\) = 4 \(\frac{x}{3} + \frac{13}{9}\) = 4 ∴ \(\frac{3X}{9} + \frac{13}{9} = \frac{36}{9}\) ∴ 3x + 13 = 36 ∴ 3x = 23 ∴ x = \(\frac{23}{3}\).

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