9.1 A constant force acts onof mass 5 kg for a duration. It increases

1.	9.1 A constant force acts onof mass 5 kg for a duration. It increases the object's velocm 3 m s^-1 to 7 m s^-1. Findtgnitude of the applied force. Nowforce was applied for a duration, what would be the final velocitypleect
Answer» Let the Force be Fmass = 5 kgtime(t) = 2 sinitial velocity(u) = 3 m/sfinal velocity(v)= 7 m/sso let the acceleration be aso a = (v - u)/t = (7 - 3)/2 = 2 m/s² So the magnitude of the applied force is 10 N and the final velocity after 5 s is v so v = u + atv = 3 + 2 x 5v = 13 m/s The final velocity after 5 s is 13 m/s

9.1 A constant force acts onof mass 5 kg for a duration. It increases the object's velocm 3 m s^-1 to 7 m s^-1. Findtgnitude of the applied force. Nowforce was applied for a duration, what would be the final velocitypleect

Answer»

Let the Force be Fmass = 5 kgtime(t) = 2 sinitial velocity(u) = 3 m/sfinal velocity(v)= 7 m/sso let the acceleration be aso a = (v - u)/t = (7 - 3)/2 = 2 m/s²

So the magnitude of the applied force is 10 N

and the final velocity after 5 s is v

so v = u + atv = 3 + 2 x 5v = 13 m/s

The final velocity after 5 s is 13 m/s

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9.1 A constant force acts onof mass 5 kg for a duration. It increases the object's velocm 3 m s^-1 to 7 m s^-1. Findtgnitude of the applied force. Nowforce was applied for a duration, what would be the final velocitypleect

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