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9. A ball is dropped from a high rise platform at t 0starting from rest. After 6 seconds another ball isthrown downwards from the same platform with aspeed 'v'. The two balls meet at t 18 s. What is thevalue of v?[AIPMT 2010](1) 75 m/s(3) 40 m/s(2) 55 m/s(4) 60 m/s

Answer»

Distance between the two balls after 6 secs = ½ * 10 * 62= 180

Relative velocity of second ball(wrt first ball) so that it can cover this distance = 180/ 12 = 15m/s

Velocity of first ball (at t= 6) = 10* 6 = 60

v= 60 + 15 =75m/s



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