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9. A constant force is applied on an object of 5 kg for 2s. Ifthe velocty of the object increases from 3ms-1 to 7 msthen find the magnitude of force applied. What would bethe final velocity of this object if the force is applied for5 5?

Answer»

Let the force be F,Mass is M,time for which it is accelerated = 2svelocity is increased from 3m/s to 7m/sso, acceleration is , a = (7-3)/2 = 2m/s²The force applied is, F = ma = (5)(2) = 10 NNow, the force is applied for 5s, the velocity after 5s will be,v=u+at=> v =3+(2)(5)=>v=13m/s , this is final velocity.



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