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9. A constant force is applied on an object of 5 kg for 2s. Ifthe velocty of the object increases from 3ms-1 to 7 msthen find the magnitude of force applied. What would bethe final velocity of this object if the force is applied for5 5? |
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Answer» Let the force be F,Mass is M,time for which it is accelerated = 2svelocity is increased from 3m/s to 7m/sso, acceleration is , a = (7-3)/2 = 2m/s²The force applied is, F = ma = (5)(2) = 10 NNow, the force is applied for 5s, the velocity after 5s will be,v=u+at=> v =3+(2)(5)=>v=13m/s , this is final velocity. |
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