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9. A load of (25 + j 25) ohm is connected across a (75 j50) volts ac supply[WBSCTE 2005, 20current is

Answer»

R = V / II = V/RI = (25 + 25j)/(75 - 50j) = 25(1 + j) /25(3 - 2j) = (1+j)/(3 - 2j)



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