9 Men working for 7 hours a day can complete a piece of work in 15 day

1.	9 Men working for 7 hours a day can complete a piece of work in 15 days. In how many days can 6 men working for 9 hours a day, complete the same piece of work ?1). $$17\frac{1}{2}days$$2). $$16\frac{3}{4}days$$3). $$16Days$$4). $$15\frac{3}{4}days$$
Answer» Solution Using, $\frac{M_1 \times D_1 \times H_1}{W_1} = \frac{M_2 \times D_2 \times H_2}{W_2}$ ALSO, $W_1 = W_2 = X$ (LET) => $\frac{9 \times 15 \times 7}{x} = \frac{6 \times D_2 \times 9}{x}$ => $15 \times 7 = 6 \times D_2$ => $D_2 = \frac{105}{6} = \frac{35}{2}$ => $D_2 = 17\frac{1}{2}$ days

9 Men working for 7 hours a day can complete a piece of work in 15 days. In how many days can 6 men working for 9 hours a day, complete the same piece of work ?1). $$17\frac{1}{2}days$$2). $$16\frac{3}{4}days$$3). $$16Days$$4). $$15\frac{3}{4}days$$

Answer»

Solution

Using, $\frac{M_1 \times D_1 \times H_1}{W_1} = \frac{M_2 \times D_2 \times H_2}{W_2}$

ALSO, $W_1 = W_2 = X$ (LET)

=> $\frac{9 \times 15 \times 7}{x} = \frac{6 \times D_2 \times 9}{x}$

=> $15 \times 7 = 6 \times D_2$

=> $D_2 = \frac{105}{6} = \frac{35}{2}$

=> $D_2 = 17\frac{1}{2}$ days