InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
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Answer» is FAVOURABLE is the CORRECT ANSWER?? am i RIGHT? |
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9 Men working for 7 hours a day can complete a piece of work in 15 days. In how many days can 6 men working for 9 hours a day, complete the same piece of work ?1). $$17\frac{1}{2}days$$2). $$16\frac{3}{4}days$$3). $$16Days$$4). $$15\frac{3}{4}days$$ |
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Answer» Solution Using, $\frac{M_1 \times D_1 \times H_1}{W_1} = \frac{M_2 \times D_2 \times H_2}{W_2}$ => $\frac{9 \times 15 \times 7}{x} = \frac{6 \times D_2 \times 9}{x}$ => $15 \times 7 = 6 \times D_2$ => $D_2 = \frac{105}{6} = \frac{35}{2}$ => $D_2 = 17\frac{1}{2}$ days |
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Who amongst the following is the author of the book "The Algebra of Infinite Justice" ?1). Kiran Desai2). Anita Desai3). Arundhati Roy4). Anita Nair |
| Answer» ARUNDHATI ROY is the ANSWER | |
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Who, among the following, is the author of 'Ignited Minds'?1). Manmohan Singh2). Poornima Advani3). Jaswant Singh4). A.P.J. Abdul Kalam |
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Answer» Solution ENGLISH LANGUAGE |
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Who amongst the following is the author of the book "The Grass is Singing" ?1). Gunter Grass2). John Maxwell Coetzee3). Harold Pinter4). Daris Lessing |
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Answer» Daris LESSING |
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Who is the author of the book `Exploring Marxist Bengal' ?1). Suman Panda2). Debraj Bhattacharya3). Swati Bose4). Chandra Banerjee |
| Answer» DEBRAJ BHATTACHARYA SEEMS CORRECT. | |
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Among B, F, J, K and W each having a different weight, F is heavier than only J. B is heavier than F and W but not as heavy as K. Who is the third heaviest among them ?1). B2). F3). K4). W |
| Answer» RIGHT ANSWER is W | |
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| Answer» RECLAMATION : - OPTION 1 | |
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Answer» Solution Clearly, both statements are REQUIRED. Let cost price = Rs. $100x$ SELLING price after profit of 20% = $\frac{120}{100} \times 100x$ = Rs. $120x$ From statement II : Selling price = Rs. 5,016 => $120x = 5016$ => $X = \frac{5016}{120} = 41.8$ $\therefore$ Cost price = $100 \times 41.8$ = Rs. $4,180$ Thus, both statements TOGETHER are required to answer the question. |
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Answer» This QUESTION was ASKED some where in previous YEAR PAPERS of SSC, and correct answer was option 4 |
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| 44. |
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Answer» Solution I : $x^2 - 23x + 120 = 0$ => $x^2 - 8x - 15X + 120 = 0$ => $x (x - 8) - 15 (x - 8) = 0$ => $(x - 8) (x - 15) = 0$ => $x = 8 , 15$ Thus, base = 8 CM and height = 15 cm (or vice versa) => Hypotenuse of right ANGLED triangle = $\sqrt{(8)^2 + (15)^2}$ = $\sqrt{64 + 225} = \sqrt{289} = 17 cm$ Since, triangle is inscribed in circle, => Radius of circle = half of hypotenuse => $r = \frac{17}{2} = 8.5$ cm $\therefore$ Area of circle = $\PI r^2$ = $\frac{22}{7} \times 8.5 \times 8.5 \approx 227 cm^2$ Thus, I alone is sufficient. Clearly, we cannot find base and height from statements II or III. Thus, they are insufficient. |
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The sum of the radius and height of a cylinder is 42 cm. Its total surface area is 3696 cm 2. What is the volume of cylinder ?1). 17428 cubic cm2). 17248 cubic cm3). 17244 cubic cm4). 17444 cubic cm |
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Answer» Solution Total surface area of cylinder => $2 \pi r H + 2 \pi r^2 = 3696$ => $2 \pi r (r + h) = 3696$ $\because (r + h) = 42$[Given] => $2 \TIMES \frac{22}{7} \times r \times 42 = 3696$ => $44 \times 6 \times r = 3696$ => $r = \frac{3696}{44 \times 6} = 14$ cm => $h = 42 - 14 = 28$ cm $\THEREFORE$ Volume of cylinder = $\pi r^2 h$ = $\frac{22}{7} \times 14 \times 14 \times 28$ = $17248 cm^3$ |
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| Answer» BADC | |