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9.The change in surface energy when a drop of radiusR splits into 8 droplets, each of radius r is (surfacetension is 7)(1) 21RT(2) 4R2T 10(3) SRT(47 TERET

Answer»

V=8v

R³=n*r³

Work done =change in surface energy

ΔU=T * Δ Α

= T * 4 π ( n r² - R²)

= T* 4π n ( R² * n^ (-2/3) - R²)

= T 4π R² ( n^{1/3} - 1 )Here,n=8

ΔU=4π R²T

∴Option 2 is correct.



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