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9.The change in surface energy when a drop of radiusR splits into 8 droplets, each of radius r is (surfacetension is 7)(1) 21RT(2) 4R2T 10(3) SRT(47 TERET |
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Answer» V=8v R³=n*r³ Work done =change in surface energy ΔU=T * Δ Α = T * 4 π ( n r² - R²) = T* 4π n ( R² * n^ (-2/3) - R²) = T 4π R² ( n^{1/3} - 1 )Here,n=8 ΔU=4π R²T ∴Option 2 is correct. |
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