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9 Two car A and B are initially at rest. Now car A starts moving with a constant velocity of 40 m/s and car B startsmoving with constant acceleration of 4 m/s?. How much time will have lapsed from before the cars again meetRPET-99)[1] 15 second[2] 20 second[3] 30 second14135 second

Answer»

Let distance covered by A be S1Let distance covered by B be S2

B will catch A when S1 = S2S = ut + 1/2 * a * t^2Therefore,

40t + (1/2 * 0 * t^2) = 0t + 1/2 * 4 * t^240t = 2t^220t = t^2

Therefore, t = 20s



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