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`90%` of a first order reaction was completed in `100 min`. How much time it will take for `80%` completion of a reactionA. `90 min`B. `80 min`C. `70 min`D. `60 min`

Answer» Correct Answer - C
`t_(90%) = log.(100)/(100-90) = log 10 = 1`
`t_(80%) = log.(100)/(100-80) = log 5 = 0.7`
`(t_(80%))/(t_(90%)) = (0.7)/(1)`
`:. t_(80%) = 100 xx 0.7 = 70 min`


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