1.

""_(92)U^(238) emits 8 alpha particles and 6 beta particles. What is the neutron / proton ratio in the product nucleus.?

Answer»

Solution :`""_(92)U^(238) overset(-8 alpha) to ""_(76)X^(206)+ 8""_(2)He^(4) (8alpha "decay")`
The RESULT of `alpha` decay
`""_(76)X^(206) overset(-6 BETA) to ""_(820)Y^(206)+ 6""_(-6)E^(0)(6 beta "decay")`
Number of PROTON = 82
Number of neutron 124
The ratio in the product nucleus= `(124)/(82)`
`("neutron")/("proton")= (62)/(41)`


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