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A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of buron and 0.144g of oxygen. Calculate the percentage composition of the compound by weight. |
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Answer» SOLUTION :The COMPOUND of OXYGEN and boron `to` boron + oxygen `0.24 g to 0.096 g + 0.144 g` Percentage of burun in the sample = `(0.096)/(0.24) xx 100 = 40` Percentage of oxygen in the sample = `(0.144)/(0.24) xx 100 = 60` Boron : 40%, Oxygen : 60% |
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