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A `0.5 kg` ball moving with a speed of `12 m//s` strikes a hard wall at an angle of `30^(@)` with the wall. It is reflected with the same speed and at the same angle . If the ball is in contact with the wall for `0.25 s`, the average force acting on the wall is A. `96N`B. `48N`C. `24N`D. `12N` |
Answer» Correct Answer - c Here, `m = 0.5kg, upsilon = 12m//s, theta = 30^(@)` `t = 0.25 s, F = ?` As Impulse = change in linear momentum `:. F xx t = 2 m upsilon sin 30^(@)` (perpendicular to the wall) `F = (2m upsilon sin 30^(@))/(t) = (2xx0.5 xx12)/(0.25) xx (1)/(2) = 24N` . |
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