A 10 cn, tall oltect is placed perpendicular to the principal nis of a

1.	A 10 cn, tall oltect is placed perpendicular to the principal nis of aconvex lens of focal length 12 em. The distance of the object from the lens18 em. Pind the nature, position and sine of the image formed
Answer» CONVEX LENS Lens formula is 1/f = 1/v - 1/u given that f=12 cm , u= -18 cm , v=? Applying the formula we get: 1/12=1/v - (-1/18)=> 1/v=1/12+(-1/18)=>1/v=1/12 - 1/18=>1/v= 1/36so v = 36 cm Thus the image is at a distance of 36 cm from the lens.The positive sign indicates it is on other side of lens as the object and so it is a virtual image. For size.magnification formula is:m=h'/h=v/u (h'=image height,h=object height,v=image distance,u=object distance)h'/10= 36/-18h'= (36/-18) * 10h'= - 20cm so,Position of image is 36 cm on other side of lens as object.Nature is virtual ImageSize of Image is 20 cm,which means it is magnified 2 times and is an erect image.

A 10 cn, tall oltect is placed perpendicular to the principal nis of aconvex lens of focal length 12 em. The distance of the object from the lens18 em. Pind the nature, position and sine of the image formed

Answer»

CONVEX LENS

Lens formula is 1/f = 1/v - 1/u

given that f=12 cm , u= -18 cm , v=?

Applying the formula we get:

1/12=1/v - (-1/18)=> 1/v=1/12+(-1/18)=>1/v=1/12 - 1/18=>1/v= 1/36so v = 36 cm

Thus the image is at a distance of 36 cm from the lens.The positive sign indicates it is on other side of lens as the object and so it is a virtual image.

For size.magnification formula is:m=h'/h=v/u (h'=image height,h=object height,v=image distance,u=object distance)h'/10= 36/-18h'= (36/-18) * 10h'= - 20cm

so,Position of image is 36 cm on other side of lens as object.Nature is virtual ImageSize of Image is 20 cm,which means it is magnified 2 times and is an erect image.

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