1.

A 120 g mass has a velocity V=(2i +5j) m/s at a certain instant. Its K E is2) 3Jb) 4Jc) 5Jd) 1.74J​

Answer»

It's been given,

mass = 120G = 0.12 Kg


and velocity = (2i + 5J m/s)

which is equal to :
\sqrt{ ({2}^{2} + {5}^{2} )} {m}^{} {s}^{ - 1} = \sqrt{29 {}^{} } m{s}^{ - 1}

Now,
The KE = 0.5mv^2.

subtituing the values we have,

0.5× 0.12 × (root 29)^2J

= 0.5 × 0.12 × 29J

= 1.74 J



Therefore (d) is your answer.


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