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A 16 kg block moving on a frictionlesshorizontal surface with a velocity of 4 m/scompresses an ideal spring and comes to rest.If the force constant of the spring be 100 N/m,then the spring is compressed by(1) 1.6 m (2) 4 m (3) 6.1 m (4) 3.2 m |
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Answer» 1/2 kx2= 1/2 mv2 1/2 X 100 X x2= 1/2 X 16 X (4)2 50 X x2= 256/2 x2= 128/50 x2= 2.56 x = 1.6 so, the spring is compressed 1.6 m |
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