`A + 2 B to C + D . ` if `- (d [A])/(dt ) = 5 xx 10^(-4)` mol `l^(-1) s^(-1)` , then `- (d[B])/(dt)` isA. `2.5 xx 10^(-4)` mol `l^(-1) s^(-1)`B. `5.0 xx 10^(-4)` mol `l^(-1) s^(-1)`C. `2.5 xx 10^(-3)` mol `l^(-1) s^(-1)`D. `1.0 xx 10^(-3)` mol `l^(-1) s^(-1)`

`A + 2 B to C + D . ` if `- (d [A])/(dt ) = 5 xx 10^(-4)` mol `l^(-1)

1.	`A + 2 B to C + D . ` if `- (d [A])/(dt ) = 5 xx 10^(-4)` mol `l^(-1) s^(-1)` , then `- (d[B])/(dt)` isA. `2.5 xx 10^(-4)` mol `l^(-1) s^(-1)`B. `5.0 xx 10^(-4)` mol `l^(-1) s^(-1)`C. `2.5 xx 10^(-3)` mol `l^(-1) s^(-1)`D. `1.0 xx 10^(-3)` mol `l^(-1) s^(-1)`
Answer» Correct Answer - d ` A + 2 B to C + D` `(-d[A])/(dt) = 5 xx 10^(-4) implies (-1)/(2) (d[B])/(dt) = 5 xx 10^(-4)` `(d[B])/(dt) = 10 xx 10^(-4) = 10^(-3)`

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`A + 2 B to C + D . ` if `- (d [A])/(dt ) = 5 xx 10^(-4)` mol `l^(-1) s^(-1)` , then `- (d[B])/(dt)` isA. `2.5 xx 10^(-4)` mol `l^(-1) s^(-1)`B. `5.0 xx 10^(-4)` mol `l^(-1) s^(-1)`C. `2.5 xx 10^(-3)` mol `l^(-1) s^(-1)`D. `1.0 xx 10^(-3)` mol `l^(-1) s^(-1)`

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