1.

A 2 C charge moving around a circle with a frequency of 6.25 10 Hz 12produces a magnetic field 6.28 tesla at the centre of the circle. The radius of the circle is

Answer»

Hello there,

◆ Answer -

r = 1.25×10^6 m

● Explanation -

# Given -

Q = 2 C

n = 6.25×10^12 Hz

B = 6.28 T

# Solution -

Current flowing

MAGNETIC field at the centre of electric field is CALCULATED by formula -

B = μ0.I / 2r

But we know, I = q / n = q.n,

B = μ0.q.n / 2r

r = μ0.q.n / 2B

r = (1.257×10^-6 × 2 × 6.25×10^12) / (2 × 6.28)

r = 1.25×10^6 m

Therefore, radius of the CIRCLE is 1.25×10^6 m.

Thanks for asking..


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