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A `2 kg` block is present against a rough wall by a force `F = 20 N` as shown in figure .Find acceleration of the block and force of friction acting on it .`(Take g = 10 m//s^(2))` |
Answer» `N = 20 N=` applied force `mu_(s) N = 16 N` and `mu_(k) N = 12 N` Driving force `F = mg` (downward) Since `F gt mu_(k) N`, block will slide downwards and kinetic frictioin of `12 N` will act in upward direction `:. a=(F - mu_(k) N)/(m)` (downward) `= (20 - 12)/(2) = 4 m//s^(2)` (downward) |
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