1.

A 20 kg body is pushed with just enough force to start it moving across a floor and the same forcecontinues to act afterwards. The co-efficient of static and kinetic friction are 0.6 & 0.2 respectively. Theacceleration of the body is

Answer»

As we know that static friction = coefficient of static friction * normal reaction of the bodythat is friction = (u)Nalso N=(m)(g) =20* 10 = 200 N ( By just taking g= 10 m/s^2static friction = 0.6 * 200 = 120 Nwhen the external force will be applied on body .it will be start moving so in this case kinetic friction= 0.2 * 200 = 40 N

so the net force will be difference of both type of friction = 120- 40 = 80 Nwe know thatF= ma soa=F/mso by butting values 80/20 =4 m/s^2 (acceleration).

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